Comments on: Ruby on Rails find_by_sql Example

By: New Ruby

New Ruby — Fri, 17 Sep 2010 08:22:37 +0000

My following code not working, please guide, thanks.

@params['body'].each do |contact|
@c = Contact.find(:all, :conditions=> ["contact_id = ?", contact["contact_id"]])

if @c.count > 0
# update record
else
# insert record
end
end

By: Mike

Mike — Wed, 25 Apr 2007 17:11:19 +0000

find :all, :conditions => [upper(artist_name) like ?', letter + "%"]

which may or may not be faster, depending on the indexes you have set up. a like query like this should be able to use a standard index on artist_name, but if you have an index on ucase(left(artist_name)), then Rick’s solution would be faster, probably.

By: rick

rick — Sat, 03 Jun 2006 21:52:36 +0000

find :all, :conditions => ['ucase(left(artist_name, 1)) = ?', letter]

By: Rory on Rails » Ruby on Rails find_all Example

Rory on Rails » Ruby on Rails find_all Example — Mon, 04 Jul 2005 04:20:50 +0000

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